35y+18=4(10y-7)-5y+46

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Solution for 35y+18=4(10y-7)-5y+46 equation: 



35y+18=4(10y-7)-5y+46

We move all terms to the left:

35y+18-(4(10y-7)-5y+46)=0



We calculate terms in parentheses: -(4(10y-7)-5y+46), so:

4(10y-7)-5y+46

We add all the numbers together, and all the variables

-5y+4(10y-7)+46

We multiply parentheses

-5y+40y-28+46

We add all the numbers together, and all the variables

35y+18

Back to the equation:

-(35y+18)



We get rid of parentheses

35y-35y-18+18=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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