35y-5=5(7y-1)

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Solution for 35y-5=5(7y-1) equation: 



35y-5=5(7y-1)

We move all terms to the left:

35y-5-(5(7y-1))=0



We calculate terms in parentheses: -(5(7y-1)), so:

5(7y-1)

We multiply parentheses

35y-5

Back to the equation:

-(35y-5)



We get rid of parentheses

35y-35y+5-5=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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