36(2*x-1)=6(x+5)+3*x

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Solution for 36(2*x-1)=6(x+5)+3*x equation: 



36(2x-1)=6(x+5)+3x

We move all terms to the left:

36(2x-1)-(6(x+5)+3x)=0

We multiply parentheses

72x-(6(x+5)+3x)-36=0



We calculate terms in parentheses: -(6(x+5)+3x), so:

6(x+5)+3x

We add all the numbers together, and all the variables

3x+6(x+5)

We multiply parentheses

3x+6x+30

We add all the numbers together, and all the variables

9x+30

Back to the equation:

-(9x+30)



We get rid of parentheses

72x-9x-30-36=0

We add all the numbers together, and all the variables

63x-66=0

We move all terms containing x to the left, all other terms to the right

63x=66

x=66/63

x=1+1/21

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