36(2x+1)=6(x+5)+3x

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Solution for 36(2x+1)=6(x+5)+3x equation:



36(2x+1)=6(x+5)+3x
We move all terms to the left:
36(2x+1)-(6(x+5)+3x)=0
We multiply parentheses
72x-(6(x+5)+3x)+36=0
We calculate terms in parentheses: -(6(x+5)+3x), so:
6(x+5)+3x
We add all the numbers together, and all the variables
3x+6(x+5)
We multiply parentheses
3x+6x+30
We add all the numbers together, and all the variables
9x+30
Back to the equation:
-(9x+30)
We get rid of parentheses
72x-9x-30+36=0
We add all the numbers together, and all the variables
63x+6=0
We move all terms containing x to the left, all other terms to the right
63x=-6
x=-6/63
x=-2/21

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