36(2x+1)=6(x+5)+3x

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Solution for 36(2x+1)=6(x+5)+3x equation: 



36(2x+1)=6(x+5)+3x

We move all terms to the left:

36(2x+1)-(6(x+5)+3x)=0

We multiply parentheses

72x-(6(x+5)+3x)+36=0



We calculate terms in parentheses: -(6(x+5)+3x), so:

6(x+5)+3x

We add all the numbers together, and all the variables

3x+6(x+5)

We multiply parentheses

3x+6x+30

We add all the numbers together, and all the variables

9x+30

Back to the equation:

-(9x+30)



We get rid of parentheses

72x-9x-30+36=0

We add all the numbers together, and all the variables

63x+6=0

We move all terms containing x to the left, all other terms to the right

63x=-6

x=-6/63

x=-2/21

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