36(x+12)=40x

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Solution for 36(x+12)=40x equation: 



36(x+12)=40x

We move all terms to the left:

36(x+12)-(40x)=0

We add all the numbers together, and all the variables

-40x+36(x+12)=0

We multiply parentheses

-40x+36x+432=0

We add all the numbers together, and all the variables

-4x+432=0

We move all terms containing x to the left, all other terms to the right

-4x=-432

x=-432/-4

x=+108

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