36(y-4)=32(y+4)

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Solution for 36(y-4)=32(y+4) equation: 



36(y-4)=32(y+4)

We move all terms to the left:

36(y-4)-(32(y+4))=0

We multiply parentheses

36y-(32(y+4))-144=0



We calculate terms in parentheses: -(32(y+4)), so:

32(y+4)

We multiply parentheses

32y+128

Back to the equation:

-(32y+128)



We get rid of parentheses

36y-32y-128-144=0

We add all the numbers together, and all the variables

4y-272=0

We move all terms containing y to the left, all other terms to the right

4y=272

y=272/4

y=68

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