36*36+d*d=96*96

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Solution for 36*36+d*d=96*96 equation:



36*36+d*d=96*96
We move all terms to the left:
36*36+d*d-(96*96)=0
We add all the numbers together, and all the variables
d*d+36*36-9216=0
We add all the numbers together, and all the variables
d*d-7920=0
Wy multiply elements
d^2-7920=0
a = 1; b = 0; c = -7920;
Δ = b2-4ac
Δ = 02-4·1·(-7920)
Δ = 31680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{31680}=\sqrt{576*55}=\sqrt{576}*\sqrt{55}=24\sqrt{55}$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{55}}{2*1}=\frac{0-24\sqrt{55}}{2} =-\frac{24\sqrt{55}}{2} =-12\sqrt{55} $
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{55}}{2*1}=\frac{0+24\sqrt{55}}{2} =\frac{24\sqrt{55}}{2} =12\sqrt{55} $

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