36+(b*b)=324

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Solution for 36+(b*b)=324 equation:



36+(b*b)=324
We move all terms to the left:
36+(b*b)-(324)=0
We add all the numbers together, and all the variables
(+b*b)+36-324=0
We add all the numbers together, and all the variables
(+b*b)-288=0
We get rid of parentheses
b*b-288=0
Wy multiply elements
b^2-288=0
a = 1; b = 0; c = -288;
Δ = b2-4ac
Δ = 02-4·1·(-288)
Δ = 1152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1152}=\sqrt{576*2}=\sqrt{576}*\sqrt{2}=24\sqrt{2}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{2}}{2*1}=\frac{0-24\sqrt{2}}{2} =-\frac{24\sqrt{2}}{2} =-12\sqrt{2} $
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{2}}{2*1}=\frac{0+24\sqrt{2}}{2} =\frac{24\sqrt{2}}{2} =12\sqrt{2} $

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