36+2(k-3)=-2(2+k)

Solution for 36+2(k-3)=-2(2+k) equation:

36+2(k-3)=-2(2+k)

We move all terms to the left:

36+2(k-3)-(-2(2+k))=0

We add all the numbers together, and all the variables

2(k-3)-(-2(k+2))+36=0

We multiply parentheses

2k-(-2(k+2))-6+36=0


We calculate terms in parentheses: -(-2(k+2)), so:

-2(k+2)

We multiply parentheses

-2k-4

Back to the equation:

-(-2k-4)


We add all the numbers together, and all the variables

2k-(-2k-4)+30=0

We get rid of parentheses

2k+2k+4+30=0

We add all the numbers together, and all the variables

4k+34=0

We move all terms containing k to the left, all other terms to the right

4k=-34

k=-34/4

k=-8+1/2