36+20(n+11)=3(-18+10n)

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Solution for 36+20(n+11)=3(-18+10n) equation: 



36+20(n+11)=3(-18+10n)

We move all terms to the left:

36+20(n+11)-(3(-18+10n))=0

We add all the numbers together, and all the variables

20(n+11)-(3(10n-18))+36=0

We multiply parentheses

20n-(3(10n-18))+220+36=0



We calculate terms in parentheses: -(3(10n-18)), so:

3(10n-18)

We multiply parentheses

30n-54

Back to the equation:

-(30n-54)



We add all the numbers together, and all the variables

20n-(30n-54)+256=0

We get rid of parentheses

20n-30n+54+256=0

We add all the numbers together, and all the variables

-10n+310=0

We move all terms containing n to the left, all other terms to the right

-10n=-310

n=-310/-10

n=+31

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