36+3x+(2x+12)=180

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Solution for 36+3x+(2x+12)=180 equation: 



36+3x+(2x+12)=180

We move all terms to the left:

36+3x+(2x+12)-(180)=0

We add all the numbers together, and all the variables

3x+(2x+12)-144=0

We get rid of parentheses

3x+2x+12-144=0

We add all the numbers together, and all the variables

5x-132=0

We move all terms containing x to the left, all other terms to the right

5x=132

x=132/5

x=26+2/5

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