36+4v=6(2v-2)

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Solution for 36+4v=6(2v-2) equation: 



36+4v=6(2v-2)

We move all terms to the left:

36+4v-(6(2v-2))=0



We calculate terms in parentheses: -(6(2v-2)), so:

6(2v-2)

We multiply parentheses

12v-12

Back to the equation:

-(12v-12)



We get rid of parentheses

4v-12v+12+36=0

We add all the numbers together, and all the variables

-8v+48=0

We move all terms containing v to the left, all other terms to the right

-8v=-48

v=-48/-8

v=+6

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