36-(2c+4)=2(c+6)=c

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Solution for 36-(2c+4)=2(c+6)=c equation:



36-(2c+4)=2(c+6)=c
We move all terms to the left:
36-(2c+4)-(2(c+6))=0
We get rid of parentheses
-2c-(2(c+6))-4+36=0
We calculate terms in parentheses: -(2(c+6)), so:
2(c+6)
We multiply parentheses
2c+12
Back to the equation:
-(2c+12)
We add all the numbers together, and all the variables
-2c-(2c+12)+32=0
We get rid of parentheses
-2c-2c-12+32=0
We add all the numbers together, and all the variables
-4c+20=0
We move all terms containing c to the left, all other terms to the right
-4c=-20
c=-20/-4
c=+5

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