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36-(2x+7)(2x+7)=0
We multiply parentheses ..
-(+4x^2+14x+14x+49)+36=0
We get rid of parentheses
-4x^2-14x-14x-49+36=0
We add all the numbers together, and all the variables
-4x^2-28x-13=0
a = -4; b = -28; c = -13;
Δ = b2-4ac
Δ = -282-4·(-4)·(-13)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-24}{2*-4}=\frac{4}{-8} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+24}{2*-4}=\frac{52}{-8} =-6+1/2 $
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