36-(3c+4)=2(c+4)+4

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Solution for 36-(3c+4)=2(c+4)+4 equation: 



36-(3c+4)=2(c+4)+4

We move all terms to the left:

36-(3c+4)-(2(c+4)+4)=0

We get rid of parentheses

-3c-(2(c+4)+4)-4+36=0



We calculate terms in parentheses: -(2(c+4)+4), so:

2(c+4)+4

We multiply parentheses

2c+8+4

We add all the numbers together, and all the variables

2c+12

Back to the equation:

-(2c+12)



We add all the numbers together, and all the variables

-3c-(2c+12)+32=0

We get rid of parentheses

-3c-2c-12+32=0

We add all the numbers together, and all the variables

-5c+20=0

We move all terms containing c to the left, all other terms to the right

-5c=-20

c=-20/-5

c=+4

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