36-(3c+4)=2(c+7)+7

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Solution for 36-(3c+4)=2(c+7)+7 equation: 



36-(3c+4)=2(c+7)+7

We move all terms to the left:

36-(3c+4)-(2(c+7)+7)=0

We get rid of parentheses

-3c-(2(c+7)+7)-4+36=0



We calculate terms in parentheses: -(2(c+7)+7), so:

2(c+7)+7

We multiply parentheses

2c+14+7

We add all the numbers together, and all the variables

2c+21

Back to the equation:

-(2c+21)



We add all the numbers together, and all the variables

-3c-(2c+21)+32=0

We get rid of parentheses

-3c-2c-21+32=0

We add all the numbers together, and all the variables

-5c+11=0

We move all terms containing c to the left, all other terms to the right

-5c=-11

c=-11/-5

c=2+1/5

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