36-(9-2m)7m=(m-9)

Solution for 36-(9-2m)7m=(m-9) equation:

36-(9-2m)7m=(m-9)

We move all terms to the left:

36-(9-2m)7m-((m-9))=0

We add all the numbers together, and all the variables

-(-2m+9)7m-((m-9))+36=0

We multiply parentheses

14m^2-63m-((m-9))+36=0


We calculate terms in parentheses: -((m-9)), so:

(m-9)

We get rid of parentheses

m-9

Back to the equation:

-(m-9)


We get rid of parentheses

14m^2-63m-m+9+36=0

We add all the numbers together, and all the variables

14m^2-64m+45=0

a = 14; b = -64; c = +45;
Δ = b2-4ac
Δ = -642-4·14·45
Δ = 1576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1576}=\sqrt{4*394}=\sqrt{4}*\sqrt{394}=2\sqrt{394}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-2\sqrt{394}}{2*14}=\frac{64-2\sqrt{394}}{28}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+2\sqrt{394}}{2*14}=\frac{64+2\sqrt{394}}{28}
$