36-2(2w+1)=4w-2(4+w)

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Solution for 36-2(2w+1)=4w-2(4+w) equation: 



36-2(2w+1)=4w-2(4+w)

We move all terms to the left:

36-2(2w+1)-(4w-2(4+w))=0

We add all the numbers together, and all the variables

-2(2w+1)-(4w-2(w+4))+36=0

We multiply parentheses

-4w-(4w-2(w+4))-2+36=0



We calculate terms in parentheses: -(4w-2(w+4)), so:

4w-2(w+4)

We multiply parentheses

4w-2w-8

We add all the numbers together, and all the variables

2w-8

Back to the equation:

-(2w-8)



We add all the numbers together, and all the variables

-4w-(2w-8)+34=0

We get rid of parentheses

-4w-2w+8+34=0

We add all the numbers together, and all the variables

-6w+42=0

We move all terms containing w to the left, all other terms to the right

-6w=-42

w=-42/-6

w=+7

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