36-2(2x+1)=8x-2(8+x)

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Solution for 36-2(2x+1)=8x-2(8+x) equation: 



36-2(2x+1)=8x-2(8+x)

We move all terms to the left:

36-2(2x+1)-(8x-2(8+x))=0

We add all the numbers together, and all the variables

-2(2x+1)-(8x-2(x+8))+36=0

We multiply parentheses

-4x-(8x-2(x+8))-2+36=0



We calculate terms in parentheses: -(8x-2(x+8)), so:

8x-2(x+8)

We multiply parentheses

8x-2x-16

We add all the numbers together, and all the variables

6x-16

Back to the equation:

-(6x-16)



We add all the numbers together, and all the variables

-4x-(6x-16)+34=0

We get rid of parentheses

-4x-6x+16+34=0

We add all the numbers together, and all the variables

-10x+50=0

We move all terms containing x to the left, all other terms to the right

-10x=-50

x=-50/-10

x=+5

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