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36-25x(2)=6(2)-5x
We move all terms to the left:
36-25x(2)-(6(2)-5x)=0
We add all the numbers together, and all the variables
-25x2-(-5x+62)+36=0
We add all the numbers together, and all the variables
-25x^2-(-5x+62)+36=0
We get rid of parentheses
-25x^2+5x-62+36=0
We add all the numbers together, and all the variables
-25x^2+5x-26=0
a = -25; b = 5; c = -26;
Δ = b2-4ac
Δ = 52-4·(-25)·(-26)
Δ = -2575
Delta is less than zero, so there is no solution for the equation
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