36-3(2x+1)=9x-3(9+x)

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Solution for 36-3(2x+1)=9x-3(9+x) equation:



36-3(2x+1)=9x-3(9+x)
We move all terms to the left:
36-3(2x+1)-(9x-3(9+x))=0
We add all the numbers together, and all the variables
-3(2x+1)-(9x-3(x+9))+36=0
We multiply parentheses
-6x-(9x-3(x+9))-3+36=0
We calculate terms in parentheses: -(9x-3(x+9)), so:
9x-3(x+9)
We multiply parentheses
9x-3x-27
We add all the numbers together, and all the variables
6x-27
Back to the equation:
-(6x-27)
We add all the numbers together, and all the variables
-6x-(6x-27)+33=0
We get rid of parentheses
-6x-6x+27+33=0
We add all the numbers together, and all the variables
-12x+60=0
We move all terms containing x to the left, all other terms to the right
-12x=-60
x=-60/-12
x=+5

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