36-7x=7x(x-5)

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Solution for 36-7x=7x(x-5) equation:



36-7x=7x(x-5)
We move all terms to the left:
36-7x-(7x(x-5))=0
We calculate terms in parentheses: -(7x(x-5)), so:
7x(x-5)
We multiply parentheses
7x^2-35x
Back to the equation:
-(7x^2-35x)
We get rid of parentheses
-7x^2-7x+35x+36=0
We add all the numbers together, and all the variables
-7x^2+28x+36=0
a = -7; b = 28; c = +36;
Δ = b2-4ac
Δ = 282-4·(-7)·36
Δ = 1792
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1792}=\sqrt{256*7}=\sqrt{256}*\sqrt{7}=16\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-16\sqrt{7}}{2*-7}=\frac{-28-16\sqrt{7}}{-14} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+16\sqrt{7}}{2*-7}=\frac{-28+16\sqrt{7}}{-14} $

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