36/(2x-3)=7/(2x+3)

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Solution for 36/(2x-3)=7/(2x+3) equation:


D( x )

2*x-3 = 0

2*x+3 = 0

2*x-3 = 0

2*x-3 = 0

2*x-3 = 0 // + 3

2*x = 3 // : 2

x = 3/2

2*x+3 = 0

2*x+3 = 0

2*x+3 = 0 // - 3

2*x = -3 // : 2

x = -3/2

x in (-oo:-3/2) U (-3/2:3/2) U (3/2:+oo)

36/(2*x-3) = 7/(2*x+3) // - 7/(2*x+3)

36/(2*x-3)-(7/(2*x+3)) = 0

36/(2*x-3)-7*(2*x+3)^-1 = 0

36/(2*x-3)-7/(2*x+3) = 0

(36*(2*x+3))/((2*x-3)*(2*x+3))+(-7*(2*x-3))/((2*x-3)*(2*x+3)) = 0

36*(2*x+3)-7*(2*x-3) = 0

58*x+129 = 0

(58*x+129)/((2*x-3)*(2*x+3)) = 0

(58*x+129)/((2*x-3)*(2*x+3)) = 0 // * (2*x-3)*(2*x+3)

58*x+129 = 0

58*x+129 = 0 // - 129

58*x = -129 // : 58

x = -129/58

x = -129/58

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