36/(3*(x-5))=6

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Solution for 36/(3*(x-5))=6 equation: 


D( x )

3*(x-5) = 0

3*(x-5) = 0

3*(x-5) = 0

( 3 )

3 = 0

x belongs to the empty set

( x-5 )

x-5 = 0 // + 5

x = 5

x in (-oo:5) U (5:+oo)

36/(3*(x-5)) = 6 // - 6

36/(3*(x-5))-6 = 0

36/(3*(x-5))+(-6*3*(x-5))/(3*(x-5)) = 0

36-6*3*(x-5) = 0

126-18*x = 0

(126-18*x)/(3*(x-5)) = 0

(126-18*x)/(3*(x-5)) = 0 // * 3*(x-5)

126-18*x = 0

126-18*x = 0 // - 126

-18*x = -126 // : -18

x = -126/(-18)

x = 7

x = 7

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