36/(n*n)=1/3

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Solution for 36/(n*n)=1/3 equation:


D( n )

n*n = 0

n*n = 0

n*n = 0

1*n^2 = 0 // : 1

n^2 = 0

n = 0

n in (-oo:0) U (0:+oo)

36/(n*n) = 1/3 // - 1/3

36/(n*n)-(1/3) = 0

36/(n*n)-1/3 = 0

36*n^-2 = 1/3 // : 36

n^-2 = 1/108

-2 < 0

1/(n^2) = 1/108 // * n^2

1 = 1/108*n^2 // : 1/108

108 = n^2

n^2 = 108 // ^ 1/2

abs(n) = 6*3^(1/2)

n = 6*3^(1/2) or n = -(6*3^(1/2))

n in { 6*3^(1/2), -(6*3^(1/2)) }

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