36/q=28/(16-q)

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Solution for 36/q=28/(16-q) equation: 



36/q=28/(16-q)

We move all terms to the left:

36/q-(28/(16-q))=0



Domain of the equation: q!=0

q∈R





Domain of the equation: (16-q))!=0

We move all terms containing q to the left, all other terms to the right

-q)!=-16

q!=-16/1

q!=-16

q∈R



We add all the numbers together, and all the variables

36/q-(28/(-1q+16))=0

We calculate fractions


(-36q)/15q^2+(-(28*q)/15q^2=0

We add all the numbers together, and all the variables

(-36q)/15q^2+(-(+28q)/15q^2=0

We multiply all the terms by the denominator


(-36q)+(-(+28q)=0



We calculate terms in parentheses: +(-(+28q), so:

-(+28q



We get rid of parentheses

-36q+(-(+28q)=0



We calculate terms in parentheses: +(-(+28q), so:

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