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360/(x-4)=x+15
We move all terms to the left:
360/(x-4)-(x+15)=0
Domain of the equation: (x-4)!=0We get rid of parentheses
We move all terms containing x to the left, all other terms to the right
x!=4
x∈R
360/(x-4)-x-15=0
We multiply all the terms by the denominator
-x*(x-4)-15*(x-4)+360=0
We multiply parentheses
-x^2+4x-15x+60+360=0
We add all the numbers together, and all the variables
-1x^2-11x+420=0
a = -1; b = -11; c = +420;
Δ = b2-4ac
Δ = -112-4·(-1)·420
Δ = 1801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{1801}}{2*-1}=\frac{11-\sqrt{1801}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{1801}}{2*-1}=\frac{11+\sqrt{1801}}{-2} $
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