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3600=x(120-x)
We move all terms to the left:
3600-(x(120-x))=0
We add all the numbers together, and all the variables
-(x(-1x+120))+3600=0
We calculate terms in parentheses: -(x(-1x+120)), so:We get rid of parentheses
x(-1x+120)
We multiply parentheses
-1x^2+120x
Back to the equation:
-(-1x^2+120x)
1x^2-120x+3600=0
We add all the numbers together, and all the variables
x^2-120x+3600=0
a = 1; b = -120; c = +3600;
Δ = b2-4ac
Δ = -1202-4·1·3600
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{120}{2}=60$
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