360=(2x)+(3x+4)+(4x+16)+(2x+10)

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Solution for 360=(2x)+(3x+4)+(4x+16)+(2x+10) equation: 



360=(2x)+(3x+4)+(4x+16)+(2x+10)

We move all terms to the left:

360-((2x)+(3x+4)+(4x+16)+(2x+10))=0



We calculate terms in parentheses: -(2x+(3x+4)+(4x+16)+(2x+10)), so:

2x+(3x+4)+(4x+16)+(2x+10)

We get rid of parentheses

2x+3x+4x+2x+4+16+10

We add all the numbers together, and all the variables

11x+30

Back to the equation:

-(11x+30)



We get rid of parentheses

-11x-30+360=0

We add all the numbers together, and all the variables

-11x+330=0

We move all terms containing x to the left, all other terms to the right

-11x=-330

x=-330/-11

x=+30

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