360=(7x-11)+(3x+6)+41+(6x-5)+(4x+7)+62

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Solution for 360=(7x-11)+(3x+6)+41+(6x-5)+(4x+7)+62 equation: 



360=(7x-11)+(3x+6)+41+(6x-5)+(4x+7)+62

We move all terms to the left:

360-((7x-11)+(3x+6)+41+(6x-5)+(4x+7)+62)=0



We calculate terms in parentheses: -((7x-11)+(3x+6)+41+(6x-5)+(4x+7)+62), so:

(7x-11)+(3x+6)+41+(6x-5)+(4x+7)+62

determiningTheFunctionDomain
(7x-11)+(3x+6)+(6x-5)+(4x+7)+41+62

We add all the numbers together, and all the variables

(7x-11)+(3x+6)+(6x-5)+(4x+7)+103

We get rid of parentheses

7x+3x+6x+4x-11+6-5+7+103

We add all the numbers together, and all the variables

20x+100

Back to the equation:

-(20x+100)



We get rid of parentheses

-20x-100+360=0

We add all the numbers together, and all the variables

-20x+260=0

We move all terms containing x to the left, all other terms to the right

-20x=-260

x=-260/-20

x=+13

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