360=30+(a+20)+(3a-10)+4a

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Solution for 360=30+(a+20)+(3a-10)+4a equation: 



360=30+(a+20)+(3a-10)+4a

We move all terms to the left:

360-(30+(a+20)+(3a-10)+4a)=0



We calculate terms in parentheses: -(30+(a+20)+(3a-10)+4a), so:

30+(a+20)+(3a-10)+4a

determiningTheFunctionDomain
(a+20)+(3a-10)+4a+30

We add all the numbers together, and all the variables

4a+(a+20)+(3a-10)+30

We get rid of parentheses

4a+a+3a+20-10+30

We add all the numbers together, and all the variables

8a+40

Back to the equation:

-(8a+40)



We get rid of parentheses

-8a-40+360=0

We add all the numbers together, and all the variables

-8a+320=0

We move all terms containing a to the left, all other terms to the right

-8a=-320

a=-320/-8

a=+40

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