360=5x(x+12)+(2x+4)

Solution for 360=5x(x+12)+(2x+4) equation:

360=5x(x+12)+(2x+4)

We move all terms to the left:

360-(5x(x+12)+(2x+4))=0


We calculate terms in parentheses: -(5x(x+12)+(2x+4)), so:

5x(x+12)+(2x+4)

We multiply parentheses

5x^2+60x+(2x+4)

We get rid of parentheses

5x^2+60x+2x+4

We add all the numbers together, and all the variables

5x^2+62x+4

Back to the equation:

-(5x^2+62x+4)


We get rid of parentheses

-5x^2-62x-4+360=0

We add all the numbers together, and all the variables

-5x^2-62x+356=0

a = -5; b = -62; c = +356;
Δ = b2-4ac
Δ = -622-4·(-5)·356
Δ = 10964
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10964}=\sqrt{4*2741}=\sqrt{4}*\sqrt{2741}=2\sqrt{2741}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-2\sqrt{2741}}{2*-5}=\frac{62-2\sqrt{2741}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+2\sqrt{2741}}{2*-5}=\frac{62+2\sqrt{2741}}{-10}
$