36=(x)+(x+3)+(2x-3)

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Solution for 36=(x)+(x+3)+(2x-3) equation:



36=(x)+(x+3)+(2x-3)
We move all terms to the left:
36-((x)+(x+3)+(2x-3))=0
We calculate terms in parentheses: -(x+(x+3)+(2x-3)), so:
x+(x+3)+(2x-3)
We get rid of parentheses
x+x+2x+3-3
We add all the numbers together, and all the variables
4x
Back to the equation:
-(4x)
We move all terms containing x to the left, all other terms to the right
-4x=-36
x=-36/-4
x=+9

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