36=(x-2)*(2x-2)

Solution for 36=(x-2)*(2x-2) equation:

36=(x-2)(2x-2)

We move all terms to the left:

36-((x-2)(2x-2))=0

We multiply parentheses ..

-((+2x^2-2x-4x+4))+36=0


We calculate terms in parentheses: -((+2x^2-2x-4x+4)), so:

(+2x^2-2x-4x+4)

We get rid of parentheses

2x^2-2x-4x+4

We add all the numbers together, and all the variables

2x^2-6x+4

Back to the equation:

-(2x^2-6x+4)


We get rid of parentheses

-2x^2+6x-4+36=0

We add all the numbers together, and all the variables

-2x^2+6x+32=0

a = -2; b = 6; c = +32;
Δ = b2-4ac
Δ = 62-4·(-2)·32
Δ = 292
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{292}=\sqrt{4*73}=\sqrt{4}*\sqrt{73}=2\sqrt{73}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{73}}{2*-2}=\frac{-6-2\sqrt{73}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{73}}{2*-2}=\frac{-6+2\sqrt{73}}{-4}
$