36=-3(22-y)+(y-4)

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Solution for 36=-3(22-y)+(y-4) equation: 



36=-3(22-y)+(y-4)

We move all terms to the left:

36-(-3(22-y)+(y-4))=0

We add all the numbers together, and all the variables

-(-3(-1y+22)+(y-4))+36=0



We calculate terms in parentheses: -(-3(-1y+22)+(y-4)), so:

-3(-1y+22)+(y-4)

We multiply parentheses

3y+(y-4)-66

We get rid of parentheses

3y+y-4-66

We add all the numbers together, and all the variables

4y-70

Back to the equation:

-(4y-70)



We get rid of parentheses

-4y+70+36=0

We add all the numbers together, and all the variables

-4y+106=0

We move all terms containing y to the left, all other terms to the right

-4y=-106

y=-106/-4

y=26+1/2

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