36=-3(24-b)+3(b-2)

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Solution for 36=-3(24-b)+3(b-2) equation: 



36=-3(24-b)+3(b-2)

We move all terms to the left:

36-(-3(24-b)+3(b-2))=0

We add all the numbers together, and all the variables

-(-3(-1b+24)+3(b-2))+36=0



We calculate terms in parentheses: -(-3(-1b+24)+3(b-2)), so:

-3(-1b+24)+3(b-2)

We multiply parentheses

3b+3b-72-6

We add all the numbers together, and all the variables

6b-78

Back to the equation:

-(6b-78)



We get rid of parentheses

-6b+78+36=0

We add all the numbers together, and all the variables

-6b+114=0

We move all terms containing b to the left, all other terms to the right

-6b=-114

b=-114/-6

b=+19

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