36=1/2(x+2)(3x+12)

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Solution for 36=1/2(x+2)(3x+12) equation: 



36=1/2(x+2)(3x+12)

We move all terms to the left:

36-(1/2(x+2)(3x+12))=0



Domain of the equation: 2(x+2)(3x+12))!=0

x∈R



We multiply parentheses ..

-(1/2(+3x^2+12x+6x+24))+36=0

We multiply all the terms by the denominator


-(1+36*2(+3x^2+12x+6x+24))=0



We calculate terms in parentheses: -(1+36*2(+3x^2+12x+6x+24)), so:

1+36*2(+3x^2+12x+6x+24)

determiningTheFunctionDomain
36*2(+3x^2+12x+6x+24)+1

Wy multiply elements

72x(++1

We use the square of the difference formula

72x(+1

Back to the equation:

-(72x(+1)



We add all the numbers together, and all the variables

-(72x1=0

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