36=9(x+5)x=

Solution for 36=9(x+5)x= equation:

36=9(x+5)x=

We move all terms to the left:

36-(9(x+5)x)=0


We calculate terms in parentheses: -(9(x+5)x), so:

9(x+5)x

We multiply parentheses

9x^2+45x

Back to the equation:

-(9x^2+45x)


We get rid of parentheses

-9x^2-45x+36=0

a = -9; b = -45; c = +36;
Δ = b2-4ac
Δ = -452-4·(-9)·36
Δ = 3321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3321}=\sqrt{81*41}=\sqrt{81}*\sqrt{41}=9\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-9\sqrt{41}}{2*-9}=\frac{45-9\sqrt{41}}{-18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+9\sqrt{41}}{2*-9}=\frac{45+9\sqrt{41}}{-18}
$