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36a^2+55a+16=0
a = 36; b = 55; c = +16;
Δ = b2-4ac
Δ = 552-4·36·16
Δ = 721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-\sqrt{721}}{2*36}=\frac{-55-\sqrt{721}}{72} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+\sqrt{721}}{2*36}=\frac{-55+\sqrt{721}}{72} $
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