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36v^2-49=0
a = 36; b = 0; c = -49;
Δ = b2-4ac
Δ = 02-4·36·(-49)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*36}=\frac{-84}{72} =-1+1/6 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*36}=\frac{84}{72} =1+1/6 $
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