36x2+-12x-3=0

Solution for 36x2+-12x-3=0 equation:

36x^2+-12x-3=0

We add all the numbers together, and all the variables

36x^2-12x=0

a = 36; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·36·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*36}=\frac{0}{72}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*36}=\frac{24}{72}
=1/3
$