36x2+3x-410=0

Solution for 36x2+3x-410=0 equation:

36x^2+3x-410=0

a = 36; b = 3; c = -410;
Δ = b2-4ac
Δ = 32-4·36·(-410)
Δ = 59049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{59049}=243$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-243}{2*36}=\frac{-246}{72}
=-3+5/12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+243}{2*36}=\frac{240}{72}
=3+1/3
$