36x2+87x+45=0

Solution for 36x2+87x+45=0 equation:

36x^2+87x+45=0

a = 36; b = 87; c = +45;
Δ = b2-4ac
Δ = 872-4·36·45
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(87)-33}{2*36}=\frac{-120}{72}
=-1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(87)+33}{2*36}=\frac{-54}{72}
=-3/4
$