36x2-12x+22=21

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Solution for 36x2-12x+22=21 equation: 



36x^2-12x+22=21

We move all terms to the left:

36x^2-12x+22-(21)=0

We add all the numbers together, and all the variables

36x^2-12x+1=0

a = 36; b = -12; c = +1;
Δ = b2-4ac
Δ = -122-4·36·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{12}{72}=1/6$

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