36x2-13x-30=0

Solution for 36x2-13x-30=0 equation:

36x^2-13x-30=0

a = 36; b = -13; c = -30;
Δ = b2-4ac
Δ = -132-4·36·(-30)
Δ = 4489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4489}=67$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-67}{2*36}=\frac{-54}{72}
=-3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+67}{2*36}=\frac{80}{72}
=1+1/9
$