If it's not what You are looking for type in the equation solver your own equation and let us solve it.
36x^2-64x=0
a = 36; b = -64; c = 0;
Δ = b2-4ac
Δ = -642-4·36·0
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4096}=64$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-64}{2*36}=\frac{0}{72} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+64}{2*36}=\frac{128}{72} =1+7/9 $
| 4h=95 | | y=275(1=0.85) | | 9=-4x+15 | | -2x+13=45 | | (5-6t)=t/5+7 | | 10=k/40 | | (3x-2)(2x+1)=6x-x-5 | | −8b+2=3b+123 | | 425-25x+50x=550 | | 6u2-21u=0 | | 4(x−8)+14=4x−17 | | −9(3−4w)−8w=28w−27 | | 3n^2=90-3n | | (2x-1)(x+4)=2x+7x-4 | | 5x-14=42 | | 3x+2+4(x-1)=8x+17 | | 35y=175 | | -53=-8x-5 | | x=5*3+11 | | 2(x−4)+6=2x−2 | | (x-5)=x+25 | | -5=b/5-3 | | 3x+18=5x-80 | | 4(3y-8)-5y=7(y-7)-4 | | 2k-7-2k=-14 | | 28x+24=28x+24 | | 2(x+9-15=-3 | | 1/4y+2=3y | | 3d+8=8d+12 | | 2(x+6)=-16 | | -3+8z=-5 | | 50+10x=-190 |