36x2-65x+25=0

Solution for 36x2-65x+25=0 equation:

36x^2-65x+25=0

a = 36; b = -65; c = +25;
Δ = b2-4ac
Δ = -652-4·36·25
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-25}{2*36}=\frac{40}{72}
=5/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+25}{2*36}=\frac{90}{72}
=1+1/4
$