37+2y-12=10y-10-3y

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Solution for 37+2y-12=10y-10-3y equation: 



37+2y-12=10y-10-3y

We move all terms to the left:

37+2y-12-(10y-10-3y)=0

We add all the numbers together, and all the variables

2y-(7y-10)+37-12=0

We add all the numbers together, and all the variables

2y-(7y-10)+25=0

We get rid of parentheses

2y-7y+10+25=0

We add all the numbers together, and all the variables

-5y+35=0

We move all terms containing y to the left, all other terms to the right

-5y=-35

y=-35/-5

y=+7

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