37-(2c+3)=4(c+5)+5

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Solution for 37-(2c+3)=4(c+5)+5 equation:


Simplifying
37 + -1(2c + 3) = 4(c + 5) + 5

Reorder the terms:
37 + -1(3 + 2c) = 4(c + 5) + 5
37 + (3 * -1 + 2c * -1) = 4(c + 5) + 5
37 + (-3 + -2c) = 4(c + 5) + 5

Combine like terms: 37 + -3 = 34
34 + -2c = 4(c + 5) + 5

Reorder the terms:
34 + -2c = 4(5 + c) + 5
34 + -2c = (5 * 4 + c * 4) + 5
34 + -2c = (20 + 4c) + 5

Reorder the terms:
34 + -2c = 20 + 5 + 4c

Combine like terms: 20 + 5 = 25
34 + -2c = 25 + 4c

Solving
34 + -2c = 25 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
34 + -2c + -4c = 25 + 4c + -4c

Combine like terms: -2c + -4c = -6c
34 + -6c = 25 + 4c + -4c

Combine like terms: 4c + -4c = 0
34 + -6c = 25 + 0
34 + -6c = 25

Add '-34' to each side of the equation.
34 + -34 + -6c = 25 + -34

Combine like terms: 34 + -34 = 0
0 + -6c = 25 + -34
-6c = 25 + -34

Combine like terms: 25 + -34 = -9
-6c = -9

Divide each side by '-6'.
c = 1.5

Simplifying
c = 1.5

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