37-1(2c+3)=4(1c+5)+1c

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Solution for 37-1(2c+3)=4(1c+5)+1c equation:



37-1(2c+3)=4(1c+5)+1c
We move all terms to the left:
37-1(2c+3)-(4(1c+5)+1c)=0
We add all the numbers together, and all the variables
-1(2c+3)-(4(c+5)+1c)+37=0
We calculate terms in parentheses: -(4(c+5)+1c), so:
4(c+5)+1c
We add all the numbers together, and all the variables
c+4(c+5)
We multiply parentheses
c+4c+20
We add all the numbers together, and all the variables
5c+20
Back to the equation:
-(5c+20)
We get rid of parentheses
-1(2c+3)-5c-20+37=0
We add all the numbers together, and all the variables
-5c-1(2c+3)+17=0
We move all terms containing c to the left, all other terms to the right
-5c-1(2c+3)=-17

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